Part 7: LABORATORY

From the chemical tests we get:

The H NMR data tells us:

The pieces then are:

O=CH, O=C-CH3 and C6H3 (trisubs. benzene), this leaves the -NH2.

Looking at the two doublets and a singlet for the 3 ArH (7 to 8 ppm) this implies that the aromatic unit is 1,2,4 substituted. At this level, it's not possible to tell the relative position of the three substituents.


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