| Qu1: | How many α-hydrogens 
        are there in each of the following aldehydes and ketones : | 
     
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            | (a) (CH3)2C=O  
              =  6 (2 x CH3) |   
            | (b) CH3CHO  
              = 3 (1 x CH3) |   
            | (c) H2C=O  
              =  0 (the 2H are attached directly to the carbonyl, 
              not the adjacent a-position) |   
            | (d) PhCHO = 0 
              (there are no H on the adjacent a-C which 
              is a substituted aromatic carbon) |   
            | (e) 2-pentanone = CH3C=OCH2CH2CH3  
              =  5 (1 x CH3 plus 1 x CH2) |   
            | (f)  3-pentanone 
              = CH3CH2C=OCH2CH3 
              =  4 (2 x CH2) |  | 
     
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      | Qu 3: |  | 
     
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            | MECHANISM OF ACID 
                CATALYSED TAUTOMERISATION |  |   
            | Step 1: First, an acid-base reaction. The Lewis basic O atom of the carbonyl 
              is protonated by the acid catalyst giving an oxonium ion.
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            | Step 2: Another acid-base reaction.  Removal of an α-hydrogen 
              by a water molecule functioning as a base allows formation of the 
              C=C and neutralises the positive charge on the O giving the enol 
              and regenerates the catalyst.
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            | MECHANISM OF BASE 
                CATALYSED TAUTOMERISATION |  |   
            | Step 1: First, an acid-base reaction. Hydroxide functions as a base and 
              removes the acidic α-hydrogen giving 
              the reactive enolate.
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            | Step 2: The negative charge is resonance stabilised to the more electronegative 
              O atom.
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            | Step 3: An acid-base reaction. The alkoxide deprotonates a water molecule 
              reforming the catalyst hydroxide and the enol
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      | Qu 4: | Acetophenone 
        is a typical ketone..... | 
     
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      | Qu 5: | As we have an 
        α,β-unsaturated ketone, then there could be 
        both direct (1,2-) or conjugate (1,4-) addition reactions: | 
     
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