Part 5: STRUCTURE DETERMINATION
Note that there is no point showing all possible answers here, so the most likely and potentially simplest answers are shown.
a. 104.08 g/mol (1.5 marks)
Solution : C4H5FO2 has a molecular weight (6 x 12.01) + (10 x 1.008) + (2 x 16.00) = 104.08 g/mol
b. 2 (1.5 marks)
Solution : the formula for index of hydrogen deficiency, IHD = 0.5 ( 2c+2-h), therefore, the IHD = 0.5 (2 x 6 + 2 - 10) = 2
c.
(3 marks)
Solution : cis-alkene (based on root chain shape) soluble in NaHCO3 suggests carboxylic acid : solubility expt.
di.
(4 marks)
Solutions : draw a cyclic ester with a chirality center (i.e. it has an sp3 C with 4 different attached groups) using wedge-hash representation. CIP priorities of the example are shown 1-3, assume the H is back and is "4" . Clockwise implies "R"
ii. Shown in figure above. Review Cahn-Ingold-Prelog priority rules (2 marks)
iii. Shown in figure above. Review assigning configuration (1 marks)
Common errors: